Sunday, February 5, 2012

Need heelp???

A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hour of labor to produce, and the wreaths take 2 hours. The labor available is limited to 80 hours per week, and the total production capacity is 60 items per week. Write a system of inequalities representing this situation, where x is the number of bouquets and y is the number of wreaths

Need heelp???
x=no. of bouquets

y=no. of wreaths



1x +2y %26lt; or = 80

x + y %26lt; or = 60
Reply:x=bouquets , y = wreaths

[hours] x + 2y %26lt;80

[items] x + y %26lt; 60
Reply:You should make a sketch of this to figure out the inequalities. If x is hours and y is products, we have starting at 0,0 and going clockwise from

Point A= 80,0 (labor constraint)

The origin

Point B=0,60 (product constaint)

Point C= 60,60 (max production of boquets)

The line y=120-x, which passes through point C

(trade-off between boquets and wreaths)

Point D=80,40 (max production of wreaths)

The line x=80

(never mind, I didn't read the problem. Just ignore me and look at the other answers)

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